Functional

## Description

General purpose function objects.

## Variables

constexpr auto | boost::hana::always
| Return a constant function returning `x` regardless of the argument(s) it is invoked with. More...
constexpr auto | boost::hana::apply
| Invokes a Callable with the given arguments. More...
template<std::size_t n>
constexpr auto | boost::hana::arg
| Return the `n`th passed argument. More...
constexpr auto | boost::hana::capture
| Create a function capturing the given variables. More...
constexpr auto | boost::hana::compose
| Return the composition of two functions or more. More...
template<std::size_t n>
constexpr auto | boost::hana::curry
| Curry a function up to the given number of arguments. More...
constexpr auto | boost::hana::demux
| Invoke a function with the results of invoking other functions on its arguments. More...
constexpr auto | boost::hana::fix
| Return a function computing the fixed point of a function. More...
constexpr auto | boost::hana::flip
| Invoke a function with its two first arguments reversed. More...
constexpr auto | boost::hana::id
| The identity function – returns its argument unchanged. More...
constexpr auto | boost::hana::infix
| Return an equivalent function that can also be applied in infix notation. More...
template<std::size_t n>
constexpr auto | boost::hana::iterate
| Applies another function `n` times to its argument. More...
constexpr auto | boost::hana::lockstep
| Invoke a function with the result of invoking other functions on its arguments, in lockstep. More...
constexpr auto | boost::hana::on
| Invoke a function with the result of invoking another function on each argument. More...
constexpr auto | boost::hana::overload
| Pick one of several functions to call based on overload resolution. More...
constexpr auto | boost::hana::overload_linearly
| Call the first function that produces a valid call expression. More...
constexpr auto | boost::hana::partial
| Partially apply a function to some arguments. More...
constexpr unspecified | boost::hana::_ {}
| Create simple functions representing C++ operators inline. More...
constexpr auto | boost::hana::reverse_partial
| Partially apply a function to some arguments. More...

## Variable Documentation

constexpr auto boost::hana::always

`#include <boost/hana/functional/always.hpp>`

Initial value:
= [](auto&& x) {
return [perfect-capture](auto const& ...y) -> decltype(auto) {
return forwarded(x);
};
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Return a constant function returning `x` regardless of the argument(s) it is invoked with.

Specifically, `always(x)` is a function such that

always(x)(y...) == x

for any `y...`. A copy of `x` is made and it is owned by the `always(x)` function. When `always(x)` is called, it will return a reference to the `x` it owns. This reference is valid as long as `always(x)` is in scope.

### Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/functional/always.hpp>
namespace hana = boost::hana;
static_assert(hana::always(1)() == 1, "");
static_assert(hana::always('2')(1, 2, 3) == '2', "");
int main() { }

constexpr auto boost::hana::apply

`#include <boost/hana/functional/apply.hpp>`

Initial value:
= [](auto&& f, auto&& ...x) -> decltype(auto) {
return forwarded(f)(forwarded(x)...);
}

Invokes a Callable with the given arguments.

This is equivalent to std::invoke that will be added in C++17. However, `apply` is a function object instead of a function, which makes it possible to pass it to higher-order algorithms.

Parameters

  f | A Callable to be invoked with the given arguments.
  x... | The arguments to call `f` with. The number of `x...` must match the arity of `f`.

## Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/functional/apply.hpp>
#include <boost/hana/plus.hpp>
namespace hana = boost::hana;
static_assert(hana::apply(hana::plus, 1, 2) == 3, "");
int main() { }

Referenced by boost::hana::literals::operator""_c(), and boost::hana::literals::operator""_s().

template<std::size_t n>

constexpr auto boost::hana::arg

`#include <boost/hana/functional/arg.hpp>`

Initial value:
= [](auto&& x1, ..., auto&& xm) -> decltype(auto) {
return forwarded(xn);
}

Return the `n`th passed argument.

Specifically, `arg<n>(x1, ..., xn, ..., xm)` is equivalent to `xn`. Note that indexing starts at 1, so `arg<1>` returns the 1st argument, `arg<2>` the 2nd and so on. Using `arg<0>` is an error. Passing less than `n` arguments to `arg<n>` is also an error.

Template Parameters

  n | An unsigned integer representing the argument to return. `n` must be positive (meaning nonzero).

Parameters

  x1,...,xm | A variadic pack of arguments from which the `n`th one is returned.

### Discussion: could `n` be dynamic?

We could have chosen `arg` to be used like `arg(n)(x...)` instead of `arg<n>(x...)`. Provided all the arguments were of the same type, it would then be possible for `n` to only be known at runtime. However, we would then lose the ability to assert the in-boundedness of `n` statically.

### Rationale for `n` being a non-type template parameter

I claim that the only interesting use case is with a compile-time `n`, which means that the usage would become `arg(int_<n>)(x...)`, which is more cumbersome to write than `arg<n>(x...)`. This is open for discussion.

### Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/functional/arg.hpp>
namespace hana = boost::hana;
// hana::arg<0>(1, '2', 3.3); // static assertion (regardless of the number of arguments)
static_assert(hana::arg<1>(1, '2', 3.3) == 1, "");
static_assert(hana::arg<2>(1, '2', 3.3) == '2', "");
static_assert(hana::arg<3>(1, '2', 3.3) == 3.3, "");
// hana::arg<4>(1, '2', 3.3); // static assertion
int main() { }

constexpr auto boost::hana::capture

`#include <boost/hana/functional/capture.hpp>`

Initial value:
= [](auto&& ...variables) {
return [perfect-capture](auto&& f) {
return [perfect-capture](auto&& ...args) -> decltype(auto) {
return forwarded(f)(forwarded(variables)..., forwarded(args)...);
};
};
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Create a function capturing the given variables.

Given 0 or more variables, `capture` creates a closure that can be used to partially apply a function. This is very similar to `partial`, except that `capture` allows the partially applied function to be specified later. Specifically, `capture(vars...)` is a function object taking a function `f` and returning `f` partially applied to `vars...`. In other words,

capture(vars...)(f)(args...) == f(vars..., args...)

Note
  The arity of `f` must match the total number of arguments passed to it, i.e. `sizeof...(vars) + sizeof...(args)`.

## Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/assert.hpp>
#include <boost/hana/config.hpp>
#include <boost/hana/functional/capture.hpp>
namespace hana = boost::hana;
int main() {
BOOST_HANA_CONSTEXPR_LAMBDA auto sum = [](auto x, auto y, auto z) {
return x + y + z;
};
BOOST_HANA_CONSTEXPR_CHECK(hana::capture(1, 2, 3)(sum)() == 6);
BOOST_HANA_CONSTEXPR_CHECK(hana::capture(1, 2)(sum)(3) == 6);
}

constexpr auto boost::hana::compose

`#include <boost/hana/functional/compose.hpp>`

Initial value:
= [](auto&& f1, auto&& f2, ..., auto&& fn) {
return [perfect-capture](auto&& x, auto&& ...xs) -> decltype(auto) {
return forwarded(f1)(
forwarded(f2)(
...
forwarded(fn)(forwarded(x))
),
forwarded(xs)...
);
}
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Return the composition of two functions or more.

`compose` is defined inductively. When given more than two functions, `compose(f, g, h...)` is equivalent to `compose(f, compose(g, h...))`. When given two functions, `compose(f, g)` is a function such that

compose(f, g)(x, y...) == f(g(x), y...)

If you need composition of the form `f(g(x, y...))`, use `demux` instead.

Note
  `compose` is an associative operation; `compose(f, compose(g, h))` is equivalent to `compose(compose(f, g), h)`.

### Proof of associativity

compose(f, compose(g, h))(x, xs...) == f(compose(g, h)(x), xs...)
== f(g(h(x)), xs...)
compose(compose(f, g), h)(x, xs...) == compose(f, g)(h(x), xs...)
== f(g(h(x)), xs...)

### Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/assert.hpp>
#include <boost/hana/config.hpp>
#include <boost/hana/functional/compose.hpp>
namespace hana = boost::hana;
int main() {
BOOST_HANA_CONSTEXPR_LAMBDA auto to_char = [](int x) {
return static_cast<char>(x + 48);
};
BOOST_HANA_CONSTEXPR_LAMBDA auto increment = [](auto x) {
return x + 1;
};
BOOST_HANA_CONSTEXPR_CHECK(hana::compose(to_char, increment)(3) == '4');
}
template<std::size_t n>

constexpr auto boost::hana::curry

`#include <boost/hana/functional/curry.hpp>`

Initial value:
= [](auto&& f) {
return [perfect-capture](auto&& x1) {
return [perfect-capture](auto&& x2) {
...
return [perfect-capture](auto&& xn) -> decltype(auto) {
return forwarded(f)(
forwarded(x1), forwarded(x2), ..., forwarded(xn)
);
};
};
};
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Curry a function up to the given number of arguments.

Currying is a technique in which we consider a function taking multiple arguments (or, equivalently, a tuple of arguments), and turn it into a function which takes a single argument and returns a function to handle the remaining arguments. To help visualize, let's denote the type of a function `f` which takes arguments of types `X1, ..., Xn` and returns a `R` as

(X1, ..., Xn) -> R

Then, currying is the process of taking `f` and turning it into an equivalent function (call it `g`) of type

X1 -> (X2 -> (... -> (Xn -> R)))

This gives us the following equivalence, where `x1`, ..., `xn` are objects of type `X1`, ..., `Xn` respectively:

f(x1, ..., xn) == g(x1)...(xn)

Currying can be useful in several situations, especially when working with higher-order functions.

This `curry` utility is an implementation of currying in C++. Specifically, `curry<n>(f)` is a function such that

curry<n>(f)(x1)...(xn) == f(x1, ..., xn)

Note that the `n` has to be specified explicitly because the existence of functions with variadic arguments in C++ make it impossible to know when currying should stop.

Unlike usual currying, this implementation also allows a curried function to be called with several arguments at a time. Hence, the following always holds

curry<n>(f)(x1, ..., xk) == curry<n - k>(f)(x1)...(xk)

Of course, this requires `k` to be less than or equal to `n`; failure to satisfy this will trigger a static assertion. This syntax is supported because it makes curried functions usable where normal functions are expected.

Another "extension" is that `curry<0>(f)` is supported: `curry<0>(f)` is a nullary function; whereas the classical definition for currying seems to leave this case undefined, as nullary functions don't make much sense in purely functional languages.

## Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/assert.hpp>
#include <boost/hana/config.hpp>
#include <boost/hana/functional/curry.hpp>
namespace hana = boost::hana;
int main() {
BOOST_HANA_CONSTEXPR_LAMBDA auto add = [](auto x, auto y, auto z) {
return x + y + z;
};
BOOST_HANA_CONSTEXPR_CHECK(hana::curry<3>(add)(1)(2)(3) == 1 + 2 + 3);
BOOST_HANA_CONSTEXPR_CHECK(hana::curry<3>(add)(1)(2, 3) == hana::curry<3>(add)(1)(2)(3));
BOOST_HANA_CONSTEXPR_CHECK(hana::curry<3>(add)(1, 2, 3) == hana::curry<3>(add)(1)(2)(3));
// curry with a nullary function
BOOST_HANA_CONSTEXPR_LAMBDA auto two = []() {
return 2;
};
BOOST_HANA_CONSTEXPR_CHECK(hana::curry<0>(two)() == two());
}

constexpr auto boost::hana::demux

`#include <boost/hana/functional/demux.hpp>`

Initial value:
= [](auto&& f) {
return [perfect-capture](auto&& ...g) {
return [perfect-capture](auto&& ...x) -> decltype(auto) {
return forwarded(f)(forwarded(g)(x...)...);
};
};
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Invoke a function with the results of invoking other functions on its arguments.

Specifically, `demux(f)(g...)` is a function such that

demux(f)(g...)(x...) == f(g(x...)...)

Each `g` is called with all the arguments, and then `f` is called with the result of each `g`. Hence, the arity of `f` must match the number of `g`s.

This is called `demux` because of a vague similarity between this device and a demultiplexer in signal processing. `demux` takes what can be seen as a continuation (`f`), a bunch of functions to split a signal (`g...`) and zero or more arguments representing the signal (`x...`). Then, it calls the continuation with the result of splitting the signal with whatever functions where given.

Note
  When used with two functions only, `demux` is associative. In other words (and noting `demux(f, g) = demux(f)(g)` to ease the notation), it is true that `demux(demux(f, g), h) == demux(f, demux(g, h))`.

## Signature

The signature of `demux` is

\[ \mathtt{demux} : (B_1 \times \dotsb \times B_n \to C) \to ((A_1 \times \dotsb \times A_n \to B_1) \times \dotsb \times (A_1 \times \dotsb \times A_n \to B_n)) \to (A_1 \times \dotsb \times A_n \to C) \]

This can be rewritten more tersely as

\[ \mathtt{demux} : \left(\prod_{i=1}^n B_i \to C \right) \to \prod_{j=1}^n \left(\prod_{i=1}^n A_i \to B_j \right) \to \left(\prod_{i=1}^n A_i \to C \right) \]

## Link with normal composition

The signature of `compose` is

\[ \mathtt{compose} : (B \to C) \times (A \to B) \to (A \to C) \]

A valid observation is that this coincides exactly with the type of `demux` when used with a single unary function. Actually, both functions are equivalent:

demux(f)(g)(x) == compose(f, g)(x)

However, let's now consider the curried version of `compose`, `curry<2>(compose)`:

\[ \mathtt{curry_2(compose)} : (B \to C) \to ((A \to B) \to (A \to C)) \]

For the rest of this explanation, we'll just consider the curried version of `compose` and so we'll use `compose` instead of `curry<2>(compose)` to lighten the notation. With currying, we can now consider `compose` applied to itself:

\[ \mathtt{compose(compose, compose)} : (B \to C) \to (A_1 \to A_2 \to B) \to (A_1 \to A_2 \to C) \]

If we uncurry deeply the above expression, we obtain

\[ \mathtt{compose(compose, compose)} : (B \to C) \times (A_1 \times A_2 \to B) \to (A_1 \times A_2 \to C) \]

This signature is exactly the same as that of `demux` when given a single binary function, and indeed they are equivalent definitions. We can also generalize this further by considering `compose(compose(compose, compose), compose)`:

\[ \mathtt{compose(compose(compose, compose), compose)} : (B \to C) \to (A_1 \to A_2 \to A_3 \to B) \to (A_1 \to A_2 \to A_3 \to C) \]

which uncurries to

\[ \mathtt{compose(compose(compose, compose), compose)} : (B \to C) \times (A_1 \times A_2 \times A_3 \to B) \to (A_1 \times A_2 \times A_3 \to C) \]

This signature is exactly the same as that of `demux` when given a single ternary function. Hence, for a single n-ary function `g`, `demux(f)(g)` is equivalent to the n-times composition of `compose` with itself, applied to `g` and `f`:

demux(f)(g) == fold_left([compose, ..., compose], id, compose)(g, f)
// ^^^^^^^^^^^^^^^^^^^^^ n times

More information on this insight can be seen here. Also, I'm not sure how this insight could be generalized to more than one function `g`, or if that is even possible.

## Proof of associativity in the binary case

As explained above, `demux` is associative when it is used with two functions only. Indeed, given functions `f`, `g` and `h` with suitable signatures, we have

demux(f)(demux(g)(h))(x...) == f(demux(g)(h)(x...))
== f(g(h(x...)))

On the other hand, we have

demux(demux(f)(g))(h)(x...) == demux(f)(g)(h(x...))
== f(g(h(x...)))

and hence `demux` is associative in the binary case.

## Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/equal.hpp>
#include <boost/hana/functional/demux.hpp>
#include <boost/hana/functional/placeholder.hpp>
#include <boost/hana/tuple.hpp>
namespace hana = boost::hana;
using hana::_;
constexpr auto f = hana::demux(hana::make_tuple)(
_ + _,
_ - _,
_ * _,
_ / _
);
static_assert(
f(10, 4) == hana::make_tuple(
10 + 4,
10 - 4,
10 * 4,
10 / 4
)
, "");
int main() { }

constexpr auto boost::hana::fix

`#include <boost/hana/functional/fix.hpp>`

Initial value:
= [](auto&& f) {
return [perfect-capture](auto&& ...x) -> decltype(auto) {
return forwarded(f)(fix(f), forwarded(x)...);
};
}
boost::hana::fix
constexpr auto fix
Return a function computing the fixed point of a function.
Definition: fix.hpp:53
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Return a function computing the fixed point of a function.

`fix` is an implementation of the Y-combinator, also called the fixed-point combinator. It encodes the idea of recursion, and in fact any recursive function can be written in terms of it.

Specifically, `fix(f)` is a function such that

fix(f)(x...) == f(fix(f), x...)

This definition allows `f` to use its first argument as a continuation to call itself recursively. Indeed, if `f` calls its first argument with `y...`, it is equivalent to calling `f(fix(f), y...)` per the above equation.

Most of the time, it is more convenient and efficient to define recursive functions without using a fixed-point combinator. However, there are some cases where `fix` provides either more flexibility (e.g. the ability to change the callback inside `f`) or makes it possible to write functions that couldn't be defined recursively otherwise.

Parameters

  f | A function called as `f(self, x...)`, where `x...` are the arguments in the `fix(f)(x...)` expression and `self` is `fix(f)`.

### Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/assert.hpp>
#include <boost/hana/config.hpp>
#include <boost/hana/functional/fix.hpp>
namespace hana = boost::hana;
BOOST_HANA_CONSTEXPR_STATELESS_LAMBDA auto factorial = hana::fix([](auto fact, auto n) -> int {
if (n == 0) return 1;
else return n * fact(n - 1);
});
int main() {
BOOST_HANA_CONSTEXPR_CHECK(factorial(5) == 120);
}

constexpr auto boost::hana::flip

`#include <boost/hana/functional/flip.hpp>`

Initial value:
= [](auto&& f) {
return [perfect-capture](auto&& x, auto&& y, auto&& ...z) -> decltype(auto) {
return forwarded(f)(forwarded(y), forwarded(x), forwarded(z)...);
};
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Invoke a function with its two first arguments reversed.

Specifically, `flip(f)` is a function such that

flip(f)(x, y, z...) == f(y, x, z...)

### Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/assert.hpp>
#include <boost/hana/config.hpp>
#include <boost/hana/functional/flip.hpp>
namespace hana = boost::hana;
BOOST_HANA_CONSTEXPR_LAMBDA auto minus = [](int x, int y, int z = 0) {
return x - y - z;
};
int main() {
BOOST_HANA_CONSTEXPR_CHECK(minus(3, 0) == 3 - 0);
BOOST_HANA_CONSTEXPR_CHECK(hana::flip(minus)(3, 0) == 0 - 3);
BOOST_HANA_CONSTEXPR_CHECK(minus(3, 0, 1) == 3 - 0 - 1);
BOOST_HANA_CONSTEXPR_CHECK(hana::flip(minus)(3, 0, 1) == 0 - 3 - 1);
}

constexpr auto boost::hana::id

`#include <boost/hana/functional/id.hpp>`

Initial value:
= [](auto&& x) -> decltype(auto) {
return forwarded(x);
}

The identity function – returns its argument unchanged.

### Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/functional/id.hpp>
namespace hana = boost::hana;
static_assert(hana::id(1) == 1, "");
static_assert(hana::id('x') == 'x', "");
int main() { }

constexpr auto boost::hana::infix

`#include <boost/hana/functional/infix.hpp>`

Initial value:
= [](auto f) {
return unspecified;
}

Return an equivalent function that can also be applied in infix notation.

Specifically, `infix(f)` is an object such that:

infix(f)(x1, ..., xn) == f(x1, ..., xn)
x ^infix(f)^ y == f(x, y)

Hence, the returned function can still be applied using the usual function call syntax, but it also gains the ability to be applied in infix notation. The infix syntax allows a great deal of expressiveness, especially when used in combination with some higher order algorithms. Since `operator^` is left-associative, `x ^infix(f)^ y` is actually parsed as `(x ^infix(f))^ y`. However, for flexibility, the order in which both arguments are applied in infix notation does not matter. Hence, it is always the case that

(x ^ infix(f)) ^ y == x ^ (infix(f) ^ y)

However, note that applying more than one argument in infix notation to the same side of the operator will result in a compile-time assertion:

(infix(f) ^ x) ^ y; // compile-time assertion
y ^ (x ^ infix(f)); // compile-time assertion

Additionally, a function created with `infix` may be partially applied in infix notation. Specifically,

(x ^ infix(f))(y1, ..., yn) == f(x, y1, ..., yn)
(infix(f) ^ y)(x1, ..., xn) == f(x1, ..., xn, y)

### Rationales

1. The `^` operator was chosen because it is left-associative and has a low enough priority so that most expressions will render the expected behavior.
2. The operator can't be customimzed because that would require more sophistication in the implementation; I want to keep it as simple as possible. There is also an advantage in having a uniform syntax for infix application.

Parameters

  f | The function which gains the ability to be applied in infix notation. The function must be at least binary; a compile-time error will be triggered otherwise.

### Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/assert.hpp>
#include <boost/hana/config.hpp>
#include <boost/hana/equal.hpp>
#include <boost/hana/functional/infix.hpp>
#include <boost/hana/pair.hpp>
namespace hana = boost::hana;
BOOST_HANA_CONSTEXPR_LAMBDA auto divmod = hana::infix([](auto x, auto y) {
// this could be a more efficient implementation
return hana::make_pair(x / y, x % y);
});
int main() {
BOOST_HANA_CONSTEXPR_CHECK((42 ^divmod^ 23) == hana::make_pair(1, 19));
}
template<std::size_t n>

constexpr auto boost::hana::iterate

`#include <boost/hana/functional/iterate.hpp>`

Initial value:
= [](auto&& f) {
return [perfect-capture](auto&& x) -> decltype(auto) {
return f(f( ... f(forwarded(x))));
};
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Applies another function `n` times to its argument.

Given a function `f` and an argument `x`, `iterate<n>(f, x)` returns the result of applying `f` `n` times to its argument. In other words,

iterate<n>(f, x) == f(f( ... f(x)))
^^^^^^^^^^ n times total

If `n == 0`, `iterate<n>(f, x)` returns the `x` argument unchanged and `f` is never applied. It is important to note that the function passed to `iterate<n>` must be a unary function. Indeed, since `f` will be called with the result of the previous `f` application, it may only take a single argument.

In addition to what's documented above, `iterate` can also be partially applied to the function argument out-of-the-box. In other words, `iterate<n>(f)` is a function object applying `f` `n` times to the argument it is called with, which means that

iterate<n>(f)(x) == iterate<n>(f, x)

This is provided for convenience, and it turns out to be especially useful in conjunction with higher-order algorithms.

## Signature

Given a function \( f : T \to T \) and `x` and argument of data type `T`, the signature is \( \mathtt{iterate_n} : (T \to T) \times T \to T \)

Template Parameters

  n | An unsigned integer representing the number of times that `f` should be applied to its argument.

Parameters

  f | A function to apply `n` times to its argument.
  x | The initial value to call `f` with.

## Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/equal.hpp>
#include <boost/hana/functional/iterate.hpp>
#include <boost/hana/functional/placeholder.hpp>
#include <boost/hana/tuple.hpp>
namespace hana = boost::hana;
constexpr auto next_10 = hana::iterate<10>(hana::_ + 1);
static_assert(next_10(3) == 13, "");
constexpr auto xs = hana::make_tuple(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);
static_assert(hana::iterate<3>(hana::make_tuple, xs) ==
hana::make_tuple(hana::make_tuple(hana::make_tuple(xs))), "");
int main() { }

constexpr auto boost::hana::lockstep

`#include <boost/hana/functional/lockstep.hpp>`

Initial value:
= [](auto&& f, auto&& ...g) {
return [perfect-capture](auto&& ...x) -> decltype(auto) {
return forwarded(f)(forwarded(g)(forwarded(x))...);
};
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Invoke a function with the result of invoking other functions on its arguments, in lockstep.

Specifically, `lockstep(f)(g1, ..., gN)` is a function such that

lockstep(f)(g1, ..., gN)(x1, ..., xN) == f(g1(x1), ..., gN(xN))

Since each `g` is invoked on its corresponding argument in lockstep, the number of arguments must match the number of `g`s.

## Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/functional/lockstep.hpp>
#include <boost/hana/plus.hpp>
namespace hana = boost::hana;
constexpr int to_int(char c) {
return static_cast<int>(c) - 48;
}
constexpr int increment(int i) {
return i + 1;
}
static_assert(hana::lockstep(hana::plus)(to_int, increment)('3', 4) == 3 + 5, "");
int main() { }

constexpr auto boost::hana::on

`#include <boost/hana/functional/on.hpp>`

Initial value:
= infix([](auto&& f, auto&& g) {
return [perfect-capture](auto&& ...x) -> decltype(auto) {
return forwarded(f)(g(forwarded(x))...);
};
})
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45
boost::hana::infix
constexpr auto infix
Return an equivalent function that can also be applied in infix notation.
Definition: infix.hpp:79

Invoke a function with the result of invoking another function on each argument.

Specifically, `on(f, g)` is a function such that

on(f, g)(x...) == f(g(x)...)

For convenience, `on` also supports infix application as provided by `infix`.

Note
  `on` is associative, i.e. `on(f, on(g, h))` is equivalent to `on(on(f, g), h)`.

### Proof of associativity

on(f, on(g, h))(xs...) == f(on(g, h)(xs)...)
== f(g(h(xs))...)
on(on(f, g), h)(xs...) == on(f, g)(h(xs)...)
== f(g(h(xs))...)

### Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/first.hpp>
#include <boost/hana/functional/on.hpp>
#include <boost/hana/integral_constant.hpp>
#include <boost/hana/less.hpp>
#include <boost/hana/pair.hpp>
#include <boost/hana/plus.hpp>
#include <boost/hana/sort.hpp>
#include <boost/hana/tuple.hpp>
#include <boost/hana/type.hpp>
namespace hana = boost::hana;
// infix application
constexpr auto sorted = hana::sort.by(hana::less ^hana::on^ hana::first, hana::make_tuple(
hana::make_pair(hana::int_c<3>, 'x'),
hana::make_pair(hana::int_c<1>, hana::type_c<void>),
hana::make_pair(hana::int_c<2>, 9876)
));
static_assert(sorted == hana::make_tuple(
hana::make_pair(hana::int_c<1>, hana::type_c<void>),
hana::make_pair(hana::int_c<2>, 9876),
hana::make_pair(hana::int_c<3>, 'x')
), "");
// function call syntax
constexpr auto x = hana::make_pair(1, 2);
constexpr auto y = hana::make_pair(10, 20);
static_assert(hana::on(hana::plus, hana::first)(x, y) == 1 + 10, "");
int main() { }

constexpr auto boost::hana::overload

`#include <boost/hana/functional/overload.hpp>`

Initial value:
= [](auto&& f1, auto&& f2, ..., auto&& fn) {
return [perfect-capture](auto&& ...x) -> decltype(auto) {
return forwarded(fk)(forwarded(x)...);
};
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Pick one of several functions to call based on overload resolution.

Specifically, `overload(f1, f2, ..., fn)` is a function object such that

overload(f1, f2, ..., fn)(x...) == fk(x...)

where `fk` is the function of `f1, ..., fn` that would be called if overload resolution was performed amongst that set of functions only. If more than one function `fk` would be picked by overload resolution, then the call is ambiguous.

### Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/assert.hpp>
#include <boost/hana/functional/overload.hpp>
#include <iostream>
#include <string>
namespace hana = boost::hana;
auto on_string = [](std::string const& s) {
std::cout << "matched std::string: " << s << std::endl;
return s;
};
auto on_int = [](int i) {
std::cout << "matched int: " << i << std::endl;
return i;
};
auto f = hana::overload(on_int, on_string);
int main() {
// prints "matched int: 1"
BOOST_HANA_RUNTIME_CHECK(f(1) == 1);
// prints "matched std::string: abcdef"
BOOST_HANA_RUNTIME_CHECK(f("abcdef") == std::string{"abcdef"});
}

constexpr auto boost::hana::overload_linearly

`#include <boost/hana/functional/overload_linearly.hpp>`

Initial value:
= [](auto&& f1, auto&& f2, ..., auto&& fn) {
return [perfect-capture](auto&& ...x) -> decltype(auto) {
return forwarded(fk)(forwarded(x)...);
};
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Call the first function that produces a valid call expression.

Given functions `f1, ..., fn`, `overload_linearly(f1, ..., fn)` is a new function that calls the first `fk` producing a valid call expression with the given arguments. Specifically,

overload_linearly(f1, ..., fn)(args...) == fk(args...)

where `fk` is the first function such that `fk(args...)` is a valid expression.

## Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/assert.hpp>
#include <boost/hana/functional/overload_linearly.hpp>
#include <string>
namespace hana = boost::hana;
auto f = hana::overload_linearly(
[](int i) { return i + 1; },
[](std::string s) { return s + "d"; },
[](double) { BOOST_HANA_RUNTIME_CHECK(false && "never called"); }
);
int main() {
BOOST_HANA_RUNTIME_CHECK(f(1) == 2);
BOOST_HANA_RUNTIME_CHECK(f("abc") == "abcd");
BOOST_HANA_RUNTIME_CHECK(f(2.2) == static_cast<int>(2.2) + 1);
}

constexpr auto boost::hana::partial

`#include <boost/hana/functional/partial.hpp>`

Initial value:
= [](auto&& f, auto&& ...x) {
return [perfect-capture](auto&& ...y) -> decltype(auto) {
return forwarded(f)(forwarded(x)..., forwarded(y)...);
};
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Partially apply a function to some arguments.

Given a function `f` and some arguments, `partial` returns a new function corresponding to the partially applied function `f`. This allows providing some arguments to a function and letting the rest of the arguments be provided later. Specifically, `partial(f, x...)` is a function such that

partial(f, x...)(y...) == f(x..., y...)

Note
  The arity of `f` must match the total number of arguments passed to it, i.e. `sizeof...(x) + sizeof...(y)`.

## Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/functional/partial.hpp>
#include <boost/hana/plus.hpp>
namespace hana = boost::hana;
constexpr auto increment = hana::partial(hana::plus, 1);
static_assert(increment(2) == 3, "");
int main() { }

constexpr unspecified boost::hana::_ {}

`#include <boost/hana/functional/placeholder.hpp>`

Create simple functions representing C++ operators inline.

Specifically, `_` is an object used as a placeholder to build function objects representing calls to C++ operators. It works by overloading the operators between `_` and any object so that they return a function object which actually calls the corresponding operator on its argument(s). Hence, for any supported operator `@`:

(_ @ _)(x, y) == x @ y

Operators may also be partially applied to one argument inline:

(x @ _)(y) == x @ y
(_ @ y)(x) == x @ y

When invoked with more arguments than required, functions created with `_` will discard the superfluous instead of triggering an error:

(_ @ _)(x, y, z...) == x @ y

This makes functions created with `_` easier to use in higher-order algorithms, which sometime provide more information than necessary to their callbacks.

### Supported operators

- Arithmetic: binary `+`, binary `-`, `/`, `*`, `%`, unary `+`, unary `-`
- Bitwise: `~`, `&`, `|`, `^`, `<<`, `>>`
- Comparison: `==`, `!=`, `<`, `<=`, `>`, `>=`
- Logical: `||`, `&&`, `!`
- Member access: `*` (dereference), `[]` (array subscript)
- Other: `()` (function call)

More complex functionality like the ability to compose placeholders into larger function objects inline are not supported. This is on purpose; you should either use C++14 generic lambdas or a library like Boost.Phoenix if you need bigger guns. The goal here is to save you a couple of characters in simple situations.

### Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/functional/placeholder.hpp>
namespace hana = boost::hana;
constexpr auto plus = hana::_ + hana::_;
static_assert(plus(1, 2) == 1 + 2, "");
constexpr auto increment = hana::_ + 1;
static_assert(increment(1) == 2, "");
constexpr auto twice = 2 * hana::_;
static_assert(twice(1) == 2, "");
// Extra arguments are ignored.
static_assert(twice(1, "ignored") == 2, "");
int main() { }

constexpr auto boost::hana::reverse_partial

`#include <boost/hana/functional/reverse_partial.hpp>`

Initial value:
= [](auto&& f, auto&& ...x) {
return [perfect-capture](auto&& ...y) -> decltype(auto) {
return forwarded(f)(forwarded(y)..., forwarded(x)...);
};
}
boost::hana::capture
constexpr auto capture
Create a function capturing the given variables.
Definition: capture.hpp:45

Partially apply a function to some arguments.

Given a function `f` and some arguments, `reverse_partial` returns a new function corresponding to `f` whose last arguments are partially applied. Specifically, `reverse_partial(f, x...)` is a function such that

reverse_partial(f, x...)(y...) == f(y..., x...)

Note
  The arity of `f` must match the total number of arguments passed to it, i.e. `sizeof...(x) + sizeof...(y)`.

## Example

// Copyright Louis Dionne 2013-2017
// Distributed under the Boost Software License, Version 1.0.
// (See accompanying file LICENSE.md or copy at http://boost.org/LICENSE_1_0.txt)
#include <boost/hana/div.hpp>
#include <boost/hana/functional/reverse_partial.hpp>
namespace hana = boost::hana;
constexpr auto half = hana::reverse_partial(hana::div, 2);
static_assert(half(4) == 2, "");
static_assert(half(8) == 4, "");
int main() { }